Most Recent Oracle 1Z0-071 Exam Dumps

When you use the INTERVAL literal for months, the result is displayed in years and months if the total number of months exceeds 12.

In the query given:

SELECT INTERVAL '100' MONTH DURATION FROM DUAL;

the output will display the interval of 100 months converted to years and the remaining months. 100 months is equal to 8 years and 4 months. Hence, the correct answer is:

DURATION +08-04

A . True. When using set operators, the number and order of columns must be the same in all SELECT statements involved in the query. The data types of those columns must also be compatible.

E . True. The FOR UPDATE clause cannot be specified in a subquery or a SELECT statement that is combined with another SELECT statement by using a set operator.

B is incorrect because the column names do not need to match; only the number and data types of the columns must be compatible. C is incorrect because only the final SELECT statement in the sequence of UNION/INTERSECT/MINUS operations can have an ORDER BY clause. D is incorrect because, as of Oracle 12c, UNION ALL can be used with CLOB columns, but UNION, INTERSECT, and MINUS cannot.

To include employees with no manager in the query results, a LEFT OUTER JOIN should be used. This type of join returns all records from the left table (employees), and the matched records from the right table (managers). The result is NULL from the right side if there is no match.

Here's the modified query:

SELECT e.last_name AS emp, m.last_name AS mgr FROM employees e LEFT OUTER JOIN managers m ON e.manager_id = m.employee_id ORDER BY emp;

This ensures that even if an employee does not have a manager (i.e., e.manager_id is NULL or there is no corresponding m.employee_id), that employee will still be included in the results.

The queries that will return all the rows from the COLORS table are those that ensure every record from COLORS is selected, regardless of whether there's a matching record in the BRICKS table:

Option A:

SELECT * FROM bricks b RIGHT JOIN colors c ON b.color_rgb_hex_value = c.rgb_hex_value;

A right join will return all the rows from the right table (COLORS), with the matching rows from the left table (BRICKS). If there is no match, NULL will be returned for columns from BRICKS.

Option B:

SELECT * FROM colors c LEFT JOIN bricks b USING (rgb_hex_value);

A left join will return all the rows from the left table (COLORS), with the matching rows from the right table (BRICKS). If there is no match, NULL will be returned for columns from BRICKS. The USING clause indicates a join condition where columns with the same names are compared for equality.

Options C, D, and E will not return all the rows from the COLORS table:

Option C: The full join will return all rows from both tables, but it is not restricted to only the rows from COLORS.

Option D: An inner join will return only the matching rows between both tables, not all rows from COLORS.

Option E: This is a left join, which would typically return all rows from COLORS, but the WHERE clause restricts the result set to only those rows from COLORS that have a matching BRICK_ID in BRICKS which is greater than 0, potentially excluding rows from COLORS.

Sequences and default values in Oracle play a crucial role in providing unique values for table columns.

Statement B is correct: When a row is inserted into ORD_ITEMS without an explicit value for ORD_NO, the ORD_NO column gets the next number from the ORD_SEQ sequence due to the DEFAULT ord_seq.nextval clause.

Statement D is correct: If the ORD_SEQ sequence is dropped, Oracle would not be able to get the next value for ORD_NO from ORD_SEQ, and unless another default is specified, the default for ORD_NO would be NULL.

Statements A, C, and E are incorrect for the following reasons:

A is incorrect because the use of the sequence in the default clause of the table definition automatically grants the necessary permissions to use the sequence when inserting into the table.

C is incorrect because the sequence is defined to cycle when it reaches its MAXVALUE and not after every 5000 numbers. It is set to cycle, but the cycling event is triggered by the MAXVALUE limit.

E is incorrect because while a sequence is designed to produce unique numbers, if it cycles, it can potentially generate the same number again after reaching the MAXVALUE. This statement would only be true if there was no cycling.